Informatica interview questions (Part 1)

Following is the list of some of Informatica interview questions.We will try to come up with more questions in later posts.

Q.1 Flat file is having 10 records as input and I want to push 5 records to the target?
Ans : one variable with the name $$count at mapping variable with a Count aggregation typeand initial value for that $$count=0. Create one expression and use SETCOUNTVARIABLEv_count=SetCountVariable ($$Count) Create one filter after expression and put condition v_count <=5
Q2 What is difference between direct and indirect loading options in sessions?
Ans: Use file type direct when we are loading single file into Target. Use Indirect when we want to load multiple files through single session in the mapping

Q3 When we create a target as flat file and source as oracle. How can we have first rows as column names in flat files.
Ans :We can add a union all clause in the Source Qualifier of the Relational source to add the header values in SELECT clause, so as to populate them as header.

Q 4 How to capture the user information (Username) of the person, who is executing a workflow or session in workflow manager.
Ans : SELECT USER_NAME,WORKFLOW_NAME FROM REP_WFLOW_RUN;

Q 5 How to join two tables, which reside in two different databases in the Source qualifier.
Ans: By using DB links in SQ ,but throughput will be very slow. Joiner will be better approach in this case

Q. 6 What is a code page?
A. A code page contains encoding to specify characters in a set of one or more languages. The code page is selected based on source of the data. For example if source contains Japanese text then the code page should be selected to support Japanese text.
When a code page is chosen, the program or application for which the code page is set, refers to a specific set of data that describes the characters the application recognizes. This influences the way that application stores, receives, and sends character data.

Q 7. Is there any way to handle sequence generation over 2 billion records, As sequence generator can generate max 2 billion records
Ans
Method1
it will be done by unconnected lookup create lookup transformation on target just keep one field(id_field) and remove all remaing fields.create i/p field with same data type as out field(id_field) select return port for id_field in loook up override write a query as select nvl(max(id_field),0) from table and ' lookup condition is id_field>=in_field in exp transformation v_dummy(v)--->it always to be zero v_lkp_return iif(:lkp_target(v_dummy) ---here u can pass v_dummy value or just zero o_id_field(0).v_lkp_return+1 __.____._

Method 2
Onw way would be to use expression trans after sequence generator. Another way could be to use expression instead of sequence genearator. Here you will use variable of agg type of count to create sequences.

Q .8 What is difference between $ and $$ parameters/variables
Ans $ are System defined and $$ are User defined variables

Q 9.How to use data from SAP/Oracle Apps /Mainframe
Ans Through power exchange.

Q 10 How to find all invalid mappings in a folder
Ans we can find the invalid mappings information from the rep_all_mappings view with a query Select mapping_name from rep_all_mappings Where subject_area='Folder_Name' And parent_mapping_is_valid <>1 My Profile